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Proof step 11 from proof exactarray-addobj (previous step)

⊦ r = r0, is_referencevalue(refval(r)) ∧ refval(r) .refval ∈ addobj(r0, class, fis, st) ∧ ( refval(r) .refval ≠ jvmref → refval(r) .refval -- _type ∈ addobj(r0, class, fis, st) ∧ is_typevalue(addobj(r0, class, fis, st)[refval(r) .refval -- _type]) ∧ (addobj(r0, class, fis, st)[refval(r) .refval -- _type]) .type = mkarraytype(ty)) ∧ r ≠ jvmref ∧ r -- _length ∈ st ∧ st[r -- _length] = intval(i) ∧ is_arrayref(r, i, st) ↔ exactreftype(refval(r), mkarraytype(ty), st) ∧ r ≠ jvmref ∧ r -- _length ∈ st ∧ st[r -- _length] = intval(i) ∧ is_arrayref(r, i, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ r ≠ r0 → (r ∈ addobj(r0, class1, fis, st) ↔ r ∈ st)
Proof step 7:
⊦ r ≠ r0 → (r -- sk ∈ addobj(r0, class1, fis, st) ↔ r -- sk ∈ st)
Proof step 8:
⊦ r ≠ r0 → (addobj(r, class1, fis, st)[r0 -- sk]) = st[r0 -- sk]
Proof step 10:
⊦ r = r0, r ∈ st ∧ r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ st[r -- _type] .type = mkarraytype(ty) ∧ r ≠ jvmref ∧ r -- _length ∈ st ∧ st[r -- _length] = intval(i) ∧ is_arrayref(r, i, st) ↔ exactreftype(refval(r), mkarraytype(ty), st) ∧ r ≠ jvmref ∧ r -- _length ∈ st ∧ st[r -- _length] = intval(i) ∧ is_arrayref(r, i, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ refval(r) .refval = r], [CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]