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Proof step 2 from proof haskeys-addobj (previous step)

⊦ r = r0, hasKeys(r, sks, addobj(r0, class, [], st)) ↔ hasKeys(r, sks, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ addobj(r, class1, [], st) = st[r -- _type, typeval(mkclasstype(class1))]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ≠ r0 → ( hasKeys (r, sks, st[r0 -- sk, val]) ↔ hasKeys(r, sks, st))])]]