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Proof step 23 from proof instore-addobj-rec (previous step)

∀ r, r1, class, class1, fis1, st. r = r1 ∨ (instore(r, class, fis0, addobj(r1, class1, fis1, st)) ↔ instore(r, class, fis0, st)) ⊦ r = r1, r -- sk ∈ st ∧ st[r -- sk] = val ∧ instore(r, class, fis0, addobj(r1, class1, fis1, st)) ↔ r -- sk ∈ st ∧ st[r -- sk] = val ∧ instore(r, class, fis0, st)

User applied rule case distinction

And obtained the following new goals

Proof step 20:
r -- sk ∈ st ∧ st[r -- sk] = val ∧ instore(r, class, fis0, addobj(r1, class1, fis1, st)), ∀ r, r1, class, class1, fis1, st. r = r1 ∨ (instore(r, class, fis0, addobj(r1, class1, fis1, st)) ↔ instore(r, class, fis0, st)) ⊦ r -- sk ∈ st ∧ st[r -- sk] = val ∧ instore(r, class, fis0, st), r = r1
Proof step 22:
r -- sk ∈ st ∧ st[r -- sk] = val ∧ instore(r, class, fis0, st), ∀ r, r1, class, class1, fis1, st. r = r1 ∨ (instore(r, class, fis0, addobj(r1, class1, fis1, st)) ↔ instore(r, class, fis0, st)) ⊦ r -- sk ∈ st ∧ st[r -- sk] = val ∧ instore(r, class, fis0, addobj(r1, class1, fis1, st)), r = r1

Rule argument

[CASEDARG : pos: right 2, ()]

Additional information

[[CONCRETESIMPRULES : ()]]