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Proof step 6 from proof is_obj-put-01 (conclusion)

⊦ r ≠ r0 → (is_obj(str, r0, st[r -- sk, val]) ↔ is_obj(str, r0, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ is_obj(str, r, st) ↔ class+∃(str, st[r -- _type] .type .class) ∧ ¬ is_abstract(st[r -- _type] .type .class) ∧ is_obj(r, st)
Proof step 2:
⊦ r ≠ r0 → (is_obj(r0, st[r -- sk, val]) ↔ is_obj(r0, st))
Proof step 5:
class+∃(str, st[r0 -- _type] .type .class), is_obj(r0, st) ⊦ r = r0, is_obj(str, r0, st[r -- sk, val]), is_abstract(st[r0 -- _type] .type .class)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ≠ r0 → (st[r0 -- sk0, val][r -- sk]) = st[r -- sk]])]]