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Proof step 19 from proof is_obj-put-equiv (conclusion)

⊦ okval(st[r1 -- sk], sk .fs .type) ∧ r1 -- sk ∈ st ∧ is_fskey(sk) ∧ okval(val, sk .fs .type) ∧ sk .fs .type ≠ void_type → (is_obj(str, r, st[r1 -- sk, val]) ↔ is_obj(str, r, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ is_obj(str, r, st) ↔ class+∃(str, st[r -- _type] .type .class) ∧ ¬ is_abstract(st[r -- _type] .type .class) ∧ is_obj(r, st)
Proof step 18:
okval(st[r1 -- sk], sk .fs .type), r1 -- sk ∈ st, is_fskey(sk), okval(val, sk .fs .type), r1 ∈ st ⊦ sk .fs .type = void_type, class+∃(str, (st[r1 -- sk, val][r -- _type]) .type .class) ∧ ¬ is_abstract((st[r1 -- sk, val][r -- _type]) .type .class) ∧ is_obj(r, st[r1 -- sk, val]) ↔ is_obj(str, r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]