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Proof step 12 from proof is_valid_ref-addobj-01 (previous step)

is_obj(r, addobj(r, class, fis, st)), class+∃(str, class) ∧ ¬ is_abstract(class) ∨ is_array(str, r, addobj(r, class, fis, st)) ⊦ _type ∈ fis, is_obj(str, r, addobj(r, class, fis, st))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ is_array(str, r, st) ↔ type∃(str, st[r -- _type] .type) ∧ st[r -- _type] .type .jtelemtype ≠ void_type ∧ st[r -- _type] .type .jtelemtype ≠ abstract_type ∧ is_array(r, st)
Proof step 11:
is_obj(r, addobj(r, class, fis, st)), class+∃(str, class) ∧ ¬ is_abstract(class) ∨ type∃(str, (addobj(r, class, fis, st)[r -- _type]) .type) ∧ (addobj(r, class, fis, st)[r -- _type]) .type .jtelemtype ≠ void_type ∧ (addobj(r, class, fis, st)[r -- _type]) .type .jtelemtype ≠ abstract_type ∧ is_array(r, addobj(r, class, fis, st)) ⊦ _type ∈ fis, is_obj(str, r, addobj(r, class, fis, st))

Rule argument

[speclemmaarg: , is_array(str, r, st) ↔ type∃(str, st[r -- _type] .type) ∧ st[r -- _type] .type .jtelemtype ≠ void_type ∧ st[r -- _type] .type .jtelemtype ≠ abstract_type ∧ is_array(r, st) ,[st, r, str] → [addobj(r, class, fis, st), r, str] ,F ,okfuns , ,is-real-array-def ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addobj(r, class, fis, st), r, str)]]