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Proof step 17 from proof is_valid_ref-addobj (previous step)

⊦ r = r0, is_valid_ref(r, st) ∧ ( class+∃(str, st[r -- _type] .type .class) ∧ ¬ is_abstract(st[r -- _type] .type .class) ∧ is_obj(r, st) ∨ is_array(str, r, addobj(r0, class, fis, st))) ↔ is_obj(str, r, st) ∨ is_array(str, r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ is_valid_ref(r, st) ↔ is_obj(r, st) ∨ is_array(r, st)
Proof step 16:
⊦ r = r0, (is_obj(r, st) ∨ is_array(r, st)) ∧ ( class+∃(str, st[r -- _type] .type .class) ∧ ¬ is_abstract(st[r -- _type] .type .class) ∧ is_obj(r, st) ∨ is_array(str, r, addobj(r0, class, fis, st))) ↔ is_obj(str, r, st) ∨ is_array(str, r, st)

Rule argument

[crewrite-arg: is-valid-ref, F, [st, r] → [st, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r)]]