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Proof step 3 from proof is_valid_ref-notin (conclusion)

⊦ ¬ r ∈ st → ¬ is_valid_ref(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ is_valid_ref(str, r, st) ↔ ¬ ¬ (is_valid_ref(r, st) ∧ (is_obj(str, r, st) ∨ is_array(str, r, st)))
Proof step 2:
⊦ ¬ r ∈ st → ¬ is_valid_ref(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]