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Proof step 33 from proof isobj-subset (previous step)

is_obj(r, st), st ⊆ st1 ⊦ r ≠ jvmref ∧ r -- _type ∈ st1 ∧ is_typevalue(st1[r -- _type]) ∧ is_classtype(st1[r -- _type] .type) ∧ is_obj(r, st1[r -- _type] .type .class, st1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ is_obj(r, st) ↔ r ≠ jvmref ∧ r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ is_classtype(st[r -- _type] .type) ∧ is_obj(r, st[r -- _type] .type .class, st)
Proof step 32:
r ≠ jvmref ∧ r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ is_classtype(st[r -- _type] .type) ∧ is_obj(r, st[r -- _type] .type .class, st), st ⊆ st1 ⊦ r ≠ jvmref ∧ r -- _type ∈ st1 ∧ is_typevalue(st1[r -- _type]) ∧ is_classtype(st1[r -- _type] .type) ∧ is_obj(r, st1[r -- _type] .type .class, st1)

Rule argument

[crewrite-arg: is-any-object, F, [st, r] → [st, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r)]]