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Proof step 13 from proof isvalidref-put-array-badindex (previous step)

(is_obj(r0, st) ∨ is_array(r0, st[r0 -- i ', val])) ∧ ( class+∃(str, st[r0 -- _type] .type .class) ∧ ¬ is_abstract(st[r0 -- _type] .type .class) ∧ is_obj(r0, st) ∨ type∃(str, st[r0 -- _type] .type) ∧ st[r0 -- _type] .type .jtelemtype ≠ void_type ∧ st[r0 -- _type] .type .jtelemtype ≠ abstract_type ∧ is_array(r0, st[r0 -- i ', val])), i < 0 ⊦ class+∃(str, st[r0 -- _type] .type .class) ∧ ¬ is_abstract(st[r0 -- _type] .type .class) ∧ is_obj(r0, st) ∨ type∃(str, st[r0 -- _type] .type) ∧ st[r0 -- _type] .type .jtelemtype ≠ void_type ∧ st[r0 -- _type] .type .jtelemtype ≠ abstract_type ∧ is_array(r0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
i < 0, type∃(str, st[r0 -- _type] .type), is_array(r0, st[r0 -- i ', val]) ⊦ st[r0 -- _type] .type .jtelemtype = abstract_type, st[r0 -- _type] .type .jtelemtype = void_type, is_array(r0, st), class+∃(str, st[r0 -- _type] .type .class) ∧ ¬ is_abstract(st[r0 -- _type] .type .class) ∧ is_obj(r0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]