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Proof step 5 from proof okfieldinits-index (previous step)

sk1 = fs ', is_indexkey(sk), is_fskey(sk1), okfieldinits(fs .class, fis0), sk ∈ fis0 .keys, ∀ sk0, class0. ¬ sk0 ∈ fis0 .keys ∨ ¬ okfieldinits(class0, fis0) ∨ is_fskey(sk0) ⊦ fs .type = abstract_type, sk = sk1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
is_indexkey(sk), okfieldinits(fs .class, fis0), sk ∈ fis0 .keys, ∀ sk0, class0. ¬ sk0 ∈ fis0 .keys ∨ ¬ okfieldinits(class0, fis0) ∨ is_fskey(sk0) ⊦ fs .type = abstract_type, sk = fs '

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_fskey(fs ')])]]