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Proof step 9 from proof okfieldinits-index (previous step)

fv = sk1 × val, is_indexkey(sk), okfieldinits(class, fv ' + fis0), ∀ sk0, class0. ¬ sk0 ∈ fis0 .keys ∨ ¬ okfieldinits(class0, fis0) ∨ is_fskey(sk0) ⊦ sk ≠ sk1 ∧ ¬ sk ∈ fis0 .keys

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
is_indexkey(sk), okfieldinits(class, (sk1 × val) ' + fis0), ∀ sk0, class0. ¬ sk0 ∈ fis0 .keys ∨ ¬ okfieldinits(class0, fis0) ∨ is_fskey(sk0) ⊦ sk ≠ sk1 ∧ ¬ sk ∈ fis0 .keys

Rule argument

[emptyarg]

Additional information

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