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Proof step 13 from proof reffield-del (previous step)

is_obj(r0, st), has_reffield(r0, st -- r) ⊦ r0 = r, has_reffield(r0, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ is_obj(r, st) → (has_reffield(r, st) ↔ (∃ fs. fs ' ∈ instfields(st[r -- _type] .type .class) ∧ is_reftype(fs .type)))
Proof step 5:
⊦ r ≠ r0 → (is_obj(r0, st -- r) ↔ is_obj(r0, st))
Proof step 12:
is_obj(r0, st -- r), is_obj(r0, st), ∃ fs. fs ' ∈ instfields((st -- r)[r0 -- _type] .type .class) ∧ is_reftype(fs .type) ⊦ r0 = r, has_reffield(r0, st)

Rule argument

[crewrite-arg: has_reffield-class, F, [st, r] → [st -- r, r0]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st -- r, r0)]]