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Proof step 38 from proof reffield-del (previous step)

is_array(r0, st), 0 < st[r0 -- _length] .intval, is_reftype(st[r0 -- _type] .type .type) ∨ st[r0 -- _type] .type .type = void_type ⊦ r0 = r, has_reffield(r0, st -- r)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 37:
⊦ is_array(r, st) → (has_reffield(r, st) ↔ st[r -- _length] .intval > 0 ∧ (is_reftype(st[r -- _type] .type .type) ∨ st[r -- _type] .type .type = void_type))

Rule argument

[crewrite-arg: has_reffield-array, F, [st, r] → [st -- r, r0]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ≠ r0 → ( is_array(r0, st -- r) ↔ is_array(r0, st))], [CSIMPSEQ : ⊦ r ≠ r0 → (st -- r)[r0 -- sk0] = st[r0 -- sk0]], [CSIMPSEQ : ⊦ i > j ↔ j < i], [CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i], [CSIMPSEQ : ⊦ i < j → (¬ ¬ j ≤ i ↔ false)])], [EXTRATERMS : (st -- r, r0)]]