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Proof step 43 from proof reffield-del (previous step)

¬ ¬ is_valid_ref(r0, st), has_reffield(r0, st) ⊦ has_reffield(r0, st -- r), r0 = r

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 42:
has_reffield(r0, st), is_valid_ref(r0, st) ⊦ r0 = r, has_reffield(r0, st -- r)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]