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Proof step 45 from proof reffield-del (previous step)

⊦ r0 = r, has_reffield(r0, st -- r) ↔ has_reffield(r0, st)

User applied rule case distinction

And obtained the following new goals

Rule argument

[CASEDARG : pos: right 2, ()]

Additional information

[[CONCRETESIMPRULES : ()]]