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Proof step 10 from proof stsubset-addobj (previous step)

newref(r, st), rk ∈ st, rk ∈ st → rk ∈ addobj(r, class1, fis, st0) ∧ st[rk] = (addobj(r, class1, fis, st0)[rk]), ∀ rk. rk ∈ st → rk ∈ addobj(r, class1, fis, st0) ∧ st[rk] = (addobj(r, class1, fis, st0)[rk]) ⊦ r = jvmref, rk ∈ st0 ∧ st[rk] = st0[rk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
st[rk] = (addobj(r, class1, fis, st0)[rk]), newref(r, st), rk ∈ st, rk ∈ addobj(r, class1, fis, st0), ∀ rk. rk ∈ st → rk ∈ addobj(r, class1, fis, st0) ∧ st[rk] = (addobj(r, class1, fis, st0)[rk]) ⊦ r = jvmref, rk ∈ st0 ∧ st[rk] = st0[rk]

Rule argument

[emptyarg]

Additional information

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