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Proof step 28 from proof stsubset-addobj (conclusion)

⊦ newref(r, st) → (st ⊆ addobj(r, class1, fis, st0) ↔ st ⊆ st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
newref(r, st) ⊦ st ⊆ addobj(r, class1, fis, st0) ↔ st ⊆ st0, r = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ newref(r, st) → r ≠ jvmref])]]