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Proof step 4 from proof validref-addobj-01 (conclusion)

⊦ ¬ _type ∈ fis → (is_valid_ref(r, addobj(r, class, fis, st)) ↔ is_obj(r, addobj(r, class, fis, st)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ ¬ is_obj(r, st) → (is_valid_ref(r, st) ↔ is_array(r, st))
Proof step 2:
⊦ ¬ _type ∈ fis → ¬ is_array(r, addobj(r, class, fis, st))
Proof step 3:
⊦ is_obj(r, st) → is_valid_ref(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]