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Proof step 8 from proof validref-addobj (conclusion)

⊦ r ≠ r0 → (is_valid_ref(r, addobj(r0, class, fis, st)) ↔ is_valid_ref(r, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
⊦ r = r0, is_valid_ref(r, addobj(r0, class, fis, st)) ↔ is_valid_ref(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]