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Proof step 15 from proof validref-put-01 (previous step)

⊦ r = r0, is_obj(r0, st[r -- sk, val]) ∨ is_array(r0, st[r -- sk, val]) ↔ is_valid_ref(r0, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ is_valid_ref(r, st) ↔ is_obj(r, st) ∨ is_array(r, st)
Proof step 14:
⊦ r = r0, is_obj(r0, st[r -- sk, val]) ∨ is_array(r0, st[r -- sk, val]) ↔ is_obj(r0, st) ∨ is_array(r0, st)

Rule argument

[crewrite-arg: is-valid-ref, F, [st, r] → [st, r0]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r0)]]