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Proof step 22 from proof compat-addobj (previous step)

st[_mode] = return(val, ty), compatrefs(str, st), compatstatic(str, st), _mode ∈ st, newref(r, st), is_predefined_class(class), compat(str, val, ty, st) ⊦ r = jvmref, return(val, ty) = return(noval, void_type), compat(str, val, ty, st[r -- _type, typeval(mkclasstype(class))])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ compat(str, val, ty, st) ↔ okval(val, ty) ∧ ( is_referencevalue(val) ∧ val .refval ≠ jvmref → val .refval -- _type ∈ st ∧ is_typevalue(st[val .refval -- _type]) ∧ is_reftype(st[val .refval -- _type] .type) ∧ (has_classtype(st[val .refval -- _type] .type) → tdname+∃(str, st[val .refval -- _type] .type .jtelemtype .class)) ∧ (is_classtype(st[val .refval -- _type] .type) → class+∃(str, st[val .refval -- _type] .type .class)) ∧ asgcomp(str, val, ty, st))
Proof step 21:
st[_mode] = return(val, ty), compatrefs(str, st), compatstatic(str, st), _mode ∈ st, newref(r, st), is_predefined_class(class), okval(val, ty) ∧ ( is_referencevalue(val) ∧ val .refval ≠ jvmref → val .refval -- _type ∈ st ∧ is_typevalue(st[val .refval -- _type]) ∧ is_reftype(st[val .refval -- _type] .type) ∧ (has_classtype(st[val .refval -- _type] .type) → tdname+∃(str, st[val .refval -- _type] .type .jtelemtype .class)) ∧ (is_classtype(st[val .refval -- _type] .type) → class+∃(str, st[val .refval -- _type] .type .class)) ∧ asgcomp(str, val, ty, st)) ⊦ r = jvmref, return(val, ty) = return(noval, void_type), compat(str, val, ty, st[r -- _type, typeval(mkclasstype(class))])

Rule argument

[crewrite-arg: value-compat , F , [st, ty, val, str] → [st, ty, val, str] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, ty, val, str)]]