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Proof step 26 from proof compat-addobj (
previous step
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⊦ is_subtype(str, ty1, ty2) ↔ ty1 ≤ ty2 ∧ (has_classtype(ty1) → tdname+∃(str, ty1 .jtclass)) ∧ (has_classtype(ty2) → tdname+∃(str, ty2 .jtclass))
A spec-lemma