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Proof step 8 from proof compatarray-void (previous step)

st[r -- _type] .type = mkarraytype(void_type), st[r -- _length] = intval(i0), 0 < i0, 0 ≤ i0, i < i0, r -- _length ∈ st, is_arrayref(r, i0, st), 0 ≤ i, r ∈ st, is_referencevalue(st[r -- i ']), st[r -- i '] .refval ≠ jvmref → st[r -- i '] .refval -- _type ∈ st ∧ is_typevalue(st[st[r -- i '] .refval -- _type]) ∧ is_reftype(st[st[r -- i '] .refval -- _type] .type) ∧ (has_classtype(st[st[r -- i '] .refval -- _type] .type) → tdname+∃(str, st[st[r -- i '] .refval -- _type] .type .jtelemtype .class)) ∧ (is_classtype(st[st[r -- i '] .refval -- _type] .type) → class+∃(str, st[st[r -- i '] .refval -- _type] .type .class)) ∧ is_subtype(str, st[st[r -- i '] .refval -- _type] .type, void_type) ⊦ st[r -- i '] = refval(jvmref), r = jvmref

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [st[r -- i '], r0] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (st[r -- i '], r0)]]