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Proof step 6 from proof compatval-addclass (previous step)

fis .keys = statfields(class), st[r -- _type] = typeval(ty0), okval(refval(r), ty), okfieldinits(class, fis), r ≠ jvmref → r -- _type ∈ st ∧ is_reftype(ty0) ∧ (has_classtype(ty0) → tdname+∃(str, ty0 .jtelemtype .class)) ∧ (is_classtype(ty0) → class+∃(str, ty0 .class)) ∧ (¬ is_referencevalue(refval(r)) ∨ refval(r) .refval = jvmref ∨ is_subtype(str, st[refval(r) .refval -- _type] .type, ty)) ⊦ (ty = void_type ∨ is_reftype(ty)) ∧ ( r ≠ jvmref → r -- _type ∈ addclass(class, fis, st) ∧ is_reftype(ty0) ∧ ( has_classtype(ty0) → class∃(str, ty0 .jtelemtype .class) ∨ interface∃(str, ty0 .jtelemtype .class) ∨ is_predefined_class(ty0 .jtelemtype .class)) ∧ (is_classtype(ty0) → class+∃(str, ty0 .class)) ∧ is_subtype(str, ty0, ty))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
st[r -- _type] = typeval(ty0), fis .keys = statfields(class), okfieldinits(class, fis), okval(refval(r), ty), r ≠ jvmref → r -- _type ∈ st ∧ is_reftype(ty0) ∧ (has_classtype(ty0) → tdname+∃(str, ty0 .jtelemtype .class)) ∧ (is_classtype(ty0) → class+∃(str, ty0 .class)) ∧ is_subtype(str, ty0, ty) ⊦ (ty = void_type ∨ is_reftype(ty)) ∧ ( r ≠ jvmref → r -- _type ∈ addclass(class, fis, st) ∧ is_reftype(ty0) ∧ ( has_classtype(ty0) → class∃(str, ty0 .jtelemtype .class) ∨ interface∃(str, ty0 .jtelemtype .class) ∨ is_predefined_class(ty0 .jtelemtype .class)) ∧ (is_classtype(ty0) → class+∃(str, ty0 .class)) ∧ is_subtype(str, ty0, ty))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ typeval(ty) .type = ty], [CSIMPSEQ : ⊦ refval(r) .refval = r], [CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]