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Proof step 39 from proof contains-append (previous step)

∀ str, ty, tys0. contains(str, tys1 + ty ' + tys0) ↔ contains(str, tys1 + ty ') ∧ contains(str, ty ' + tys0) ⊦ contains(str, (ty0 + tys1) + ty ' + tys0) ↔ contains(str, (ty0 + tys1) + ty ') ∧ contains(str, ty ' + tys0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
∀ str, ty, tys0. contains(str, tys1 + ty ' + tys0) ↔ contains(str, tys1 + ty ') ∧ contains(str, ty ' + tys0) ⊦ contains(str, (ty0 ' + tys1) + ty ' + tys0) ↔ contains(str, (ty0 ' + tys1) + ty ') ∧ contains(str, ty ' + tys0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ty + tys = ty ' + tys])]]