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Proof step 5 from proof contains-append (previous step)

⊦ contains(str, [] + ty ' + tys0) ↔ contains(str, [] + ty ') ∧ contains(str, ty ' + tys0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ contains(str, ty ') ↔ type∃(str, ty)
Proof step 4:
contains(str, ty ' + tys0) ⊦ type∃(str, ty)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (tys + tys0) + tys1 = tys + tys0 + tys1], [CSIMPSEQ : ⊦ [] + tys = tys])]]