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Proof step 62 from proof contains-field-def-case (previous step)

type∃(str, ty), tys .first ≤ ty, contains(str, tys), is_reftype(tys .last), is_classtype(tys .last) → ¬ interface∃(str, tys .last .class) ∧ fs ' ∈ instfields(tys .last .class), is_arraytype(tys .last) → fs ' = _length ⊦ tys = [], ∃ ty1. (ty1 ≤ ty ∧ type∃(str, ty1) ∨ contains(str, ty, ty1)) ∧ is_reftype(ty1) ∧ (is_classtype(ty1) → ¬ interface∃(str, ty1 .class) ∧ fs ' ∈ instfields(ty1 .class)) ∧ (is_arraytype(ty1) → fs ' = _length)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 61:
tys = ty0 + tys0, type∃(str, ty), ty0 ≤ ty, contains(str, tys), is_reftype(tys .last), is_classtype(tys .last) → ¬ interface∃(str, tys .last .class) ∧ fs ' ∈ instfields(tys .last .class), is_arraytype(tys .last) → fs ' = _length ⊦ tys = [], ∃ ty1. (ty1 ≤ ty ∧ type∃(str, ty1) ∨ contains(str, ty, ty1)) ∧ is_reftype(ty1) ∧ (is_classtype(ty1) → ¬ interface∃(str, ty1 .class) ∧ fs ' ∈ instfields(ty1 .class)) ∧ (is_arraytype(ty1) → fs ' = _length)

Rule argument

[speclemmaarg: tys ≠ [] ,ty = tys .first ∧ tys0 = tys .rest ↔ tys = ty + tys0 ,[tys, ty, tys0] → [tys, ty0, tys0] ,T ,list-data ,javatypes ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : tys ≠ [] ⊦ ty = tys .first ∧ tys0 = tys .rest ↔ tys = ty + tys0])], [EXTRATERMS : (tys, ty0, tys0)]]