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Proof step 62 from proof contains-levelsubset (previous step)

tys1 = tys2 + ty4 ', contains(str0, ty3, ty4) ∨ dups(tys2) ∨ ty3 ∈ tys2, tys + ty0 ' = ty3 ' + tys1, level⊆(str, str0), contains(str, ty3 ' + tys1), type∃(str, ty1), ty1 ≤ ty, is_reftype(ty), type∃(str, ty), ty0 ∈ tys1, ty3 ∈ tys, is_classtype(ty1) → ¬ interface∃(str, ty1 .class) ∧ mkfs(class, ty2, fieldvar) ' ∈ instfields(ty1 .class) ∧ ty3 ≤ ty2, is_arraytype(ty1) → ty3 ≤ ty1 .type, ∀ ty0, ty, str0, str, tys0. # tys0 < # tys → (level⊆(str, str0) ∧ contains(str, ty ' + tys0 + ty0 ') → contains(str0, ty, ty0) ∨ dups(tys0) ∨ ty ∈ tys0) ⊦ tys1 = [], contains(str0, ty, ty0), dups(tys), ty ∈ tys

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 61:
type∃(str, ty), is_reftype(ty), ty1 ≤ ty, type∃(str, ty1), contains(str, ty3 ' + tys2 + ty4 '), level⊆(str, str0), contains(str0, ty3, ty4), is_arraytype(ty1) → ty3 ≤ ty1 .type, is_classtype(ty1) → ¬ interface∃(str, ty1 .class) ∧ mkfs(class, ty2, fieldvar) ' ∈ instfields(ty1 .class) ∧ ty3 ≤ ty2, ∀ ty0, ty, str0, str, tys0. # tys0 < # (ty3 ' + tys2) → (level⊆(str, str0) ∧ contains(str, ty ' + tys0 + ty0 ') → contains(str0, ty, ty0) ∨ dups(tys0) ∨ ty ∈ tys0) ⊦ ty = ty3, contains(str0, ty, ty4), ty ∈ tys2, dups(tys2), ty3 ∈ tys2

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ dups(ty ' + tys) ↔ dups(tys) ∨ ty ∈ tys], [CSIMPSEQ : ⊦ ¬ ty ∈ ty0 ' + tys ↔ ty ≠ ty0 ∧ ¬ ty ∈ tys], [CSIMPFORWARD : ⊦ ty ' + tys = tys0 → ty ∈ tys0], [CSIMPSEQ : ⊦ ty ∈ ty0 ' ↔ ty = ty0], [CSIMPSEQ : ⊦ ty ∈ tys + tys0 ↔ ¬ ¬ (ty ∈ tys ∨ ty ∈ tys0)], [CSIMPSEQ : ⊦ tys + ty ' ≠ []], [CSIMPSEQ : ⊦ (tys + tys0) + tys1 = tys + tys0 + tys1], [CSIMPSEQ : ⊦ tys + ty ' = tys0 + ty0 ' ↔ tys = tys0 ∧ ty = ty0])]]