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Proof step 73 from proof contains-levelsubset (previous step)

level⊆(str, str0) ∧ contains(str, ty ' + tys + ty0 '), ∀ ty0, ty, str0, str, tys0. # tys0 < # tys → (level⊆(str, str0) ∧ contains(str, ty ' + tys0 + ty0 ') → contains(str0, ty, ty0) ∨ dups(tys0) ∨ ty ∈ tys0) ⊦ contains(str0, ty, ty0) ∨ dups(tys) ∨ ty ∈ tys

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 72:
contains(str, ty ' + tys + ty0 '), level⊆(str, str0), ∀ ty0, ty, str0, str, tys0. # tys0 < # tys → (level⊆(str, str0) ∧ contains(str, ty ' + tys0 + ty0 ') → contains(str0, ty, ty0) ∨ dups(tys0) ∨ ty ∈ tys0) ⊦ ty ∈ tys, dups(tys), contains(str0, ty, ty0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]