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Proof step 8 from proof contains-shortarray-01 (previous step)

⊦ tys = [], (∃ ty. is_arraytype(ty) ∧ ty .type = short_type ∧ type∃(str, ty) ∧ tys .first ≤ ty .type ∧ contains(str, tys)) ↔ tys = short_type '

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 7:
tys = ty0 + tys0 ⊦ tys = [], (∃ ty. is_arraytype(ty) ∧ ty .type = short_type ∧ type∃(str, ty) ∧ ty0 ≤ ty .type ∧ contains(str, tys)) ↔ tys = short_type '

Rule argument

[speclemmaarg: tys ≠ [] ,ty = tys .first ∧ tys0 = tys .rest ↔ tys = ty + tys0 ,[tys, ty, tys0] → [tys, ty0, tys0] ,T ,list-data ,javatypes ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : tys ≠ [] ⊦ ty = tys .first ∧ tys0 = tys .rest ↔ tys = ty + tys0])], [EXTRATERMS : (tys, ty0, tys0)]]