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Proof step 60 from proof contains-subspec (previous step)

tys + ty0 ' = ty3 + tys1 ∧ tys + ty0 ' ≠ [], type∃(str0, ty), is_reftype(ty), ty1 ≤ ty, type∃(str0, ty1), contains(str0, tys + ty0 '), type∃(str, ty), level⊆(str0, str), same-subclasses-contains(ty .jtelemtype .class, str, str0), has_classtype(ty), is_arraytype(ty1) → ty3 ≤ ty1 .type, is_classtype(ty1) → ¬ interface∃(str0, ty1 .class) ∧ mkfs(class, ty2, fieldvar) ' ∈ instfields(ty1 .class) ∧ ty3 ≤ ty2, ∀ ty0, str0, str, ty, tys0. # tys0 < # tys → ( has_classtype(ty) ∧ same-subclasses-contains(ty .jtelemtype .class, str, str0) ∧ level⊆(str0, str) ∧ type∃(str, ty) ∧ contains(str0, ty ' + tys0 + ty0 ') → contains(str, ty, ty0) ∨ dups(tys0) ∨ ty ∈ tys0) ⊦ ty ∈ tys, dups(tys), contains(str, ty, ty0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 59:
tys + ty0 ' = ty3 ' + tys1, has_classtype(ty), same-subclasses-contains(ty .jtelemtype .class, str, str0), level⊆(str0, str), type∃(str, ty), contains(str0, ty3 ' + tys1), type∃(str0, ty1), ty1 ≤ ty, is_reftype(ty), type∃(str0, ty), is_classtype(ty1) → ¬ interface∃(str0, ty1 .class) ∧ mkfs(class, ty2, fieldvar) ' ∈ instfields(ty1 .class) ∧ ty3 ≤ ty2, is_arraytype(ty1) → ty3 ≤ ty1 .type, ∀ ty0, str0, str, ty, tys0. # tys0 < # tys → ( has_classtype(ty) ∧ same-subclasses-contains(ty .jtelemtype .class, str, str0) ∧ level⊆(str0, str) ∧ type∃(str, ty) ∧ contains(str0, ty ' + tys0 + ty0 ') → contains(str, ty, ty0) ∨ dups(tys0) ∨ ty ∈ tys0) ⊦ contains(str, ty, ty0), dups(tys), ty ∈ tys, ty0 ≠ ty3 ∧ ¬ ty0 ∈ tys1, ¬ ty3 ∈ tys ∧ ty3 ≠ ty0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ty ∈ ty0 ' ↔ ty = ty0], [CSIMPSEQ : ⊦ ty ∈ tys + tys0 ↔ ¬ ¬ (ty ∈ tys ∨ ty ∈ tys0)], [CSIMPFORWARD : ⊦ ty ' + tys = tys0 → ty ∈ tys0], [CSIMPFORWARD : ⊦ tys + ty ' = tys0 → ty ∈ tys0], [CSIMPSEQ : ⊦ (tys + tys0) + tys1 = tys + tys0 + tys1], [CSIMPSEQ : ⊦ tys + ty ' ≠ []], [CSIMPSEQ : ⊦ ty + tys = ty ' + tys])]]