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Proof step 3 from proof same-subclasses (previous step)

same-subclasses-contains(class, str, str0), contains(str0, mkclasstype(class), mkclasstype(class0)), ∀ class0. contains(str0, mkclasstype(class), mkclasstype(class0)) → tdname+∃(str, class0) ⊦ tdname+∃(str, class0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 3, [QUANTTERMLIST : (class0)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (class0)]]