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Proof step 148 from proof validrefs-not-contains (previous step)

validrefs(str, r ' + r0 ' + refs, ty, st), ∀ str0, st0, ty0. ¬ contains(str0, st0[r0 -- _type] .type, st0[(r0 ' + refs) .last -- _type] .type) ∧ r0 ≠ (r0 ' + refs) .last → ¬ validrefs(str0, r0 ' + refs, ty0, st0) ⊦ refs = [], (r0 ' + refs) .last = jvmref, r = (r0 ' + refs) .last, contains(str, st[r -- _type] .type, st[(r0 ' + refs) .last -- _type] .type)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 147:
validrefs(str, r ' + r0 ' + refs, ty, st), ∀ str0, st0, ty0. ¬ contains(str0, st0[r0 -- _type] .type, st0[refs .last -- _type] .type) ∧ r0 ≠ refs .last → ¬ validrefs(str0, r0 ' + refs, ty0, st0) ⊦ refs = [], refs .last = jvmref, r = refs .last, contains(str, st[r -- _type] .type, st[refs .last -- _type] .type)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ refs ≠ [] → (r ' + refs) .last = refs .last])]]