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Proof step 150 from proof validrefs-not-contains (previous step)

acc = r0 + refs ∧ acc ≠ [], validrefs(str, r ' + acc, ty, st), ∀ str, st, ty. ¬ contains(str, st[r0 -- _type] .type, st[acc .last -- _type] .type) ∧ acc ≠ [] ∧ r0 ≠ acc .last ∧ acc .last ≠ jvmref → ¬ validrefs(str, acc, ty, st) ⊦ (r ' + acc) .last = jvmref, r = (r ' + acc) .last, contains(str, st[r -- _type] .type, st[(r ' + acc) .last -- _type] .type)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 149:
validrefs(str, r ' + r0 ' + refs, ty, st), ∀ str0, st0, ty0. ¬ contains(str0, st0[r0 -- _type] .type, st0[(r0 ' + refs) .last -- _type] .type) ∧ r0 ≠ (r0 ' + refs) .last → ¬ validrefs(str0, r0 ' + refs, ty0, st0) ⊦ (r0 ' + refs) .last = jvmref, r = (r0 ' + refs) .last, contains(str, st[r -- _type] .type, st[(r0 ' + refs) .last -- _type] .type)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ' ≠ []], [CSIMPSEQ : ⊦ ¬ refs + refs0 ≠ [] ↔ refs = [] ∧ refs0 = []], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ (r ' + r0 ' + refs) .last = (r0 ' + refs) .last], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]