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Proof step 11 from proof cyclic-addobj-other (previous step)

newref(r0, st), validrefs(str, r ' + refs0, st[r -- _type] .type, addobj(r0, class, fis, st)) ⊦ r = r0, r0 = jvmref, junkref(str, r, st), cyclic(str, r, st), ¬ r ∈ refs0 ∧ ¬ dups(refs0), ¬ validrefs(str, r ' + refs0, st[r -- _type] .type, st) ∧ ¬ r0 ∈ refs0

User applied rule cut formula

And obtained the following new goals

Proof step 5:
r0 ∈ refs0, newref(r0, st), validrefs(str, r ' + refs0, st[r -- _type] .type, addobj(r0, class, fis, st)) ⊦ r = r0, r0 = jvmref, junkref(str, r, st), cyclic(str, r, st), ¬ r ∈ refs0 ∧ ¬ dups(refs0), ¬ validrefs(str, r ' + refs0, st[r -- _type] .type, st) ∧ ¬ r0 ∈ refs0
Proof step 10:
newref(r0, st), validrefs(str, r ' + refs0, st[r -- _type] .type, addobj(r0, class, fis, st)) ⊦ r0 ∈ refs0, r = r0, r0 = jvmref, junkref(str, r, st), cyclic(str, r, st), ¬ r ∈ refs0 ∧ ¬ dups(refs0), ¬ validrefs(str, r ' + refs0, st[r -- _type] .type, st) ∧ ¬ r0 ∈ refs0

Rule argument

[fma-arg: r0 ∈ refs0]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (r0 ∈ refs0)]]