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Proof step 33 from proof cyclic-addrefarray (previous step)

is_referencevalue(vals[i→n(i)]), i < n→i(# vals), is_array(str, r, addarray(r, ty, vals, st)), is_reftype(ty), type∃(str, ty), newref(r, st), 0 ≤ i, validrefs(str, vals[i→n(i)] .refval ' + refs, ty, addarray(r, ty, vals, st)), ∀ val. val ∈ vals → ¬ junkref(str, val .refval, st) ∧ ¬ cyclic(str, val .refval, st) ∧ is_referencevalue(val) ∧ (val .refval ≠ jvmref → st[val .refval -- _type] .type ≤ ty) ⊦ r = jvmref, ty .jtelemtype = void_type, ty .jtelemtype = abstract_type, vals = [], r ≠ vals[i→n(i)] .refval ∧ ¬ r ∈ refs ∧ ¬ vals[i→n(i)] .refval ∈ refs ∧ ¬ dups(refs)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 32:
vals[i→n(i)] = refval(r0), is_referencevalue(vals[i→n(i)]), i < n→i(# vals), is_array(str, r, addarray(r, ty, vals, st)), is_reftype(ty), type∃(str, ty), newref(r, st), 0 ≤ i, validrefs(str, r0 ' + refs, ty, addarray(r, ty, vals, st)), ∀ val. val ∈ vals → ¬ junkref(str, val .refval, st) ∧ ¬ cyclic(str, val .refval, st) ∧ is_referencevalue(val) ∧ (val .refval ≠ jvmref → st[val .refval -- _type] .type ≤ ty) ⊦ r = jvmref, ty .jtelemtype = void_type, ty .jtelemtype = abstract_type, vals = [], r ≠ r0 ∧ ¬ r ∈ refs ∧ ¬ r0 ∈ refs ∧ ¬ dups(refs)

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [vals[i→n(i)], r0] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (vals[i→n(i)], r0)]]