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Proof step 11 from proof cyclic-delete (previous step)

refs = r + refs0 ∧ refs ≠ [], dups(refs), validrefs(str, refs, (st -- r0)[r -- _type] .type, st -- r0) ⊦ cyclic(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
validrefs(str, r ' + refs0, (st -- r0)[r -- _type] .type, st -- r0) ⊦ cyclic(str, r, st), ¬ r ∈ refs0 ∧ ¬ dups(refs0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ dups(r ' + refs) ↔ ¬ ¬ (r ∈ refs ∨ dups(refs))], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]