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Proof step 13 from proof cyclic-delete (previous step)

∃ refs. dups(refs) ∧ refs .first = r ∧ validrefs(str, refs, (st -- r0)[r -- _type] .type, st -- r0) ⊦ cyclic(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
dups(refs), validrefs(str, refs, (st -- r0)[refs .first -- _type] .type, st -- r0) ⊦ cyclic(str, refs .first, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]