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Proof step 7 from proof cyclic-delete (previous step)

r0 ≠ r, validrefs(str, r ' + refs0, st[r -- _type] .type, st -- r0) ⊦ ¬ r ∈ refs0 ∧ ¬ dups(refs0), ∃ refs. dups(refs) ∧ refs .first = r ∧ validrefs(str, refs, st[refs .first -- _type] .type, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
validrefs(str, r ' + refs0, st[r -- _type] .type, st -- r0) ⊦ r0 = r, ∃ refs. dups(refs) ∧ refs .first = r ∧ validrefs(str, refs, st[refs .first -- _type] .type, st), ¬ r ∈ refs0 ∧ ¬ dups(refs0)

Rule argument

[emptyarg]

Additional information

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