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Proof step 21 from proof cyclic-put-nopathex (previous step)

∃ refs, r1. ¬ dups(refs) ∧ r1 ∈ refs ∧ refs .first = r ∧ validrefs(str, refs + r1 ', st[refs .first -- _type] .type, st[r0 -- sk, val]) ⊦ ∃ refs, r1. ¬ dups(refs) ∧ r1 ∈ refs ∧ refs .first = r ∧ validrefs(str, refs + r1 ', st[refs .first -- _type] .type, st), sk = _type, path∃(str, r, r0, st), junkref(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
r1 ∈ refs, validrefs(str, refs + r1 ', st[refs .first -- _type] .type, st[r0 -- sk, val]) ⊦ sk = _type, path∃(str, refs .first, r0, st), junkref(str, refs .first, st), dups(refs), ∃ refs0, r1. ¬ dups(refs0) ∧ r1 ∈ refs0 ∧ refs0 .first = refs .first ∧ validrefs(str, refs0 + r1 ', st[refs0 .first -- _type] .type, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]