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Proof step 39 from proof cyclic-put-nopathex (previous step)

⊦ sk = _type, (∃ refs, r1. ¬ dups(refs) ∧ r1 ∈ refs ∧ refs .first = r ∧ validrefs(str, refs + r1 ', (st[r0 -- sk, val][r -- _type]) .type, st[r0 -- sk, val])) ↔ cyclic(str, r, st), path∃(str, r, r0, st), junkref(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
⊦ sk = _type, (∃ refs, r1. ¬ dups(refs) ∧ r1 ∈ refs ∧ refs .first = r ∧ validrefs(str, refs + r1 ', st[refs .first -- _type] .type, st[r0 -- sk, val])) ↔ cyclic(str, r, st), path∃(str, r, r0, st), junkref(str, r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ sk ≠ sk0 → (st[r -- sk, val][r0 -- sk0]) = st[r0 -- sk0]])]]