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Proof step 8 from proof cyclic-putbyte-01 (previous step)

r0 ∈ refs, validrefs(str, refs + r0 ', st[refs .first -- _type] .type, st), okbytearray(r1, st) ⊦ dups(refs), ∃ refs0. dups(refs0) ∧ refs0 .first = refs .first ∧ validrefs(str, refs0, st[refs0 .first -- _type] .type, st[r1 -- i ', byteval(by)])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 7:
refs = r + refs1 ∧ refs ≠ [], r0 ∈ refs, validrefs(str, refs + r0 ', st[r -- _type] .type, st), okbytearray(r1, st) ⊦ dups(refs), ∃ refs0. dups(refs0) ∧ refs0 .first = r ∧ validrefs(str, refs0, st[refs0 .first -- _type] .type, st[r1 -- i ', byteval(by)])

Rule argument

[x0lemmaarg: spec-name: list-data instance-name: references lemma-name: elim-list-c antecedent: refs ≠ [] succedent: r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 substlist: [refs, r, refs0] → [refs, r, refs1] add preconditions?: F is rewrite lemma?: F current spec?: F rotate lemma?: T replace all?: T paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, references, in-empty, ⊦ ¬ r ∈ []], [CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (refs, r, refs1)]]