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Proof step 18 from proof cyclic-subset-01 (conclusion)

⊦ cyclic(str, r, st) ∧ st ⊆ st0 ∧ ¬ junkref(str, r, st) → cyclic(str, r, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]