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Proof step 10 from proof cyclic-subset (previous step)

st ⊆ st0, validrefs(str, r ' + refs0, st0[r -- _type] .type, st0) ⊦ validrefs(str, r ' + refs0, st[r -- _type] .type, st), junkref(str, r, st), ¬ r ∈ refs0 ∧ ¬ dups(refs0)

User applied rule cut formula

And obtained the following new goals

Rule argument

[fma-arg: st0[r -- _type] = st[r -- _type]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (st0[r -- _type] = st[r -- _type])]]