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Proof step 8 from proof cyclic-subset (previous step)

∀ rk. rk ∈ st → rk ∈ st0 ∧ st[rk] = st0[rk], validrefs(str, r ' + refs0, st0[r -- _type] .type, st0) ⊦ st0[r -- _type] = st[r -- _type], validrefs(str, r ' + refs0, st[r -- _type] .type, st), junkref(str, r, st), ¬ r ∈ refs0 ∧ ¬ dups(refs0)

User applied rule all left

And obtained the following new goals

Proof step 7:
⊦ validrefs(str, jvmref ' + refs, ty, st) ↔ refs = []

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (r -- _type) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ ¬ rk ∈ st → st[rk] = ∅[rk]], [CSIMPSEQ : ⊦ ∅[rk] = noval], [CSIMPSEQ : ⊦ ¬ r -- _type ∈ st → ( junkref(str, r, st) ↔ r ≠ jvmref)])], [EXTRATERMS : (r -- _type)]]