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Proof step 105 from proof exvalidrefs-maxlength (previous step)

cyclic(str, r0, st -- r) ∨ junkref(str, r0, st -- r) ∨ (∃ refs. validrefs(str, refs, (st -- r)[refs .first -- _type] .type, st -- r) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r0 ∧ ¬ has_reffield(refs .last, st -- r)), st[r -- mkfs(class, ty, fieldvar) '] = refval(r0), is_obj(r, st), is_obj(str, r, st), mkfs(class, ty, fieldvar) ' ∈ instfields(st[r -- _type] .type .class), is_reftype(ty), st[r0 -- _type] .type ≤ ty, ∀ r, str, st0. # st0 .refs < # st .refs → ( true → cyclic(str, r, st0) ∨ junkref(str, r, st0) ∨ (∃ refs. validrefs(str, refs, st0[refs .first -- _type] .type, st0) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st0))) ⊦ r0 = jvmref, r = r0, r = jvmref, r0 = jvmref, cyclic(str, r, st), junkref(str, r0, st), ∃ refs. validrefs(str, refs, st[refs .first -- _type] .type, st) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ≠ r0 → (st -- r)[r0 -- sk0] = st[r0 -- sk0]])]]