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Proof step 155 from proof exvalidrefs-maxlength (previous step)

st[r -- 0 '] = refval(r0), validrefs(str, r0 ' + refs0, (st -- r)[r0 -- _type] .type, st -- r), st[r0 -- _type] .type ≤ st[r -- _type] .type .type, is_array(r, st), is_array(str, r, st), 0 < st[r -- _length] .intval, is_reftype(st[r -- _type] .type .type) ∨ st[r -- _type] .type .type = void_type, ∀ r, str, st0. # st0 .refs < # st .refs → ( true → cyclic(str, r, st0) ∨ junkref(str, r, st0) ∨ (∃ refs. validrefs(str, refs, st0[refs .first -- _type] .type, st0) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st0))) ⊦ r0 = jvmref, r = jvmref, junkref(str, r0, st), validrefs(str, r0 ' + refs0, st[r -- _type] .type .type, st), (st -- r)[r0 -- _type] .type ≤ st[r -- _type] .type .type, ¬ r0 ∈ refs0 ∧ ¬ dups(refs0), ∃ refs. validrefs(str, refs, st[refs .first -- _type] .type, st) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[speclemmaarg: ,r ≠ r0 → (st -- r)[r0 -- sk0] = st[r0 -- sk0] ,[sk0, r0, r, st] → [_type, r0, r, st] ,F ,storefuns , ,look-del ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])], [EXTRATERMS : (_type, r0, r, st)]]