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Proof step 206 from proof exvalidrefs-maxlength (previous step)

st[r -- 0 '] = refval(r0), st[r0 -- _type] .type ≤ st[r -- _type] .type .type, is_array(r, st), is_array(str, r, st), 0 < st[r -- _length] .intval, junkrefs(str, (r0 ' + refs) + r ', st[r0 -- _type] .type, st -- r), is_reftype(st[r -- _type] .type .type) ∨ st[r -- _type] .type .type = void_type, ∀ r, str, st0. # st0 .refs < # st .refs → ( true → cyclic(str, r, st0) ∨ junkref(str, r, st0) ∨ (∃ refs. validrefs(str, refs, st0[refs .first -- _type] .type, st0) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st0))) ⊦ r = r0, r0 = jvmref, r = jvmref, r ∈ refs, junkref(str, r0, st), dups(r ' + (r0 ' + refs) + r ') ∧ (r ' + (r0 ' + refs) + r ') .first = r ∧ validrefs(str, r ' + (r0 ' + refs) + r ', st[(r ' + (r0 ' + refs) + r ') .first -- _type] .type, st), ∃ refs. validrefs(str, refs, st[refs .first -- _type] .type, st) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 205:
st[r -- 0 '] = refval(r0), st[r0 -- _type] .type ≤ st[r -- _type] .type .type, is_array(r, st), is_array(str, r, st), 0 < st[r -- _length] .intval, junkrefs(str, (r0 ' + refs) + r ', st[r0 -- _type] .type, st -- r), is_reftype(st[r -- _type] .type .type) ∨ st[r -- _type] .type .type = void_type, ∀ r, str, st0. # st0 .refs < # st .refs → ( true → cyclic(str, r, st0) ∨ junkref(str, r, st0) ∨ (∃ refs. validrefs(str, refs, st0[refs .first -- _type] .type, st0) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st0))) ⊦ r = r0, r0 = jvmref, r = jvmref, r ∈ refs, junkref(str, r0, st), validrefs(str, r ' + (r0 ' + refs) + r ', st[r -- _type] .type, st), ∃ refs. validrefs(str, refs, st[refs .first -- _type] .type, st) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (r ' + refs) .first = r], [CSIMPSEQ : ⊦ r ≠ r0 → (r ∈ r0 ' + refs ↔ r ∈ refs)], [CSIMPSEQ : ⊦ r ∈ r0 ' ↔ r = r0], [CSIMPSEQ : ⊦ r ∈ refs + refs0 ↔ ¬ ¬ (r ∈ refs ∨ r ∈ refs0)], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ dups(refs + r ') ↔ r ∈ refs ∨ dups(refs)], [CSIMPSEQ : ⊦ dups(r ' + refs) ↔ dups(refs) ∨ r ∈ refs])]]