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Proof step 250 from proof exvalidrefs-maxlength (previous step)

refs0 ≠ [], st[r -- 0 '] = refval(r0), validrefs(str, r0 ' + refs0, st[r0 -- _type] .type, st -- r), st[r0 -- _type] .type ≤ st[r -- _type] .type .type, is_array(r, st), is_array(str, r, st), 0 < st[r -- _length] .intval, is_reftype(st[r -- _type] .type .type) ∨ st[r -- _type] .type .type = void_type, ∀ r, str, st0. # st0 .refs < # st .refs → ( true → cyclic(str, r, st0) ∨ junkref(str, r, st0) ∨ (∃ refs. validrefs(str, refs, st0[refs .first -- _type] .type, st0) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st0))) ⊦ r = r0, r0 = jvmref, r = jvmref, r0 ∈ refs0, dups(refs0), has_reffield(refs0 .last, st -- r), junkref(str, r0, st), cyclic(str, r, st), r ∈ refs0, ∃ refs. validrefs(str, refs, st[refs .first -- _type] .type, st) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 249:
st[r -- 0 '] = refval(r0), 0 < st[r -- _length] .intval, is_array(str, r, st), is_array(r, st), st[r0 -- _type] .type ≤ st[r -- _type] .type .type, validrefs(str, r0 ' + refs0, st[r0 -- _type] .type, st -- r), is_reftype(st[r -- _type] .type .type) ∨ st[r -- _type] .type .type = void_type, ∀ r, str, st0. # st0 .refs < # st .refs → ( true → cyclic(str, r, st0) ∨ junkref(str, r, st0) ∨ (∃ refs. validrefs(str, refs, st0[refs .first -- _type] .type, st0) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st0))) ⊦ refs0 = [], r = jvmref, r0 = jvmref, r = r0, r ∈ refs0, cyclic(str, r, st), junkref(str, r0, st), has_reffield(refs0 .last, st -- r), dups(refs0), r0 ∈ refs0, ∃ refs. validrefs(str, refs, st[refs .first -- _type] .type, st) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]